How many formula units are there in 325 grams PbO2?

There are approximately 8.183 × 10²³ units of PbO₂ in 325 grams of PbO₂

Explanation:

The given mass of PbO₂ = 325 grams

The molar mass of PbO₂ = 239.2 g/mol

The number of moles of PbO₂ in 325 grams of PbO₂ is given by the formula for the number of moles of a chemical compound in a given sample of the compound as follows;

For the given PbO₂ compound, in the question, we have;

The number of units of PbO₂ in one mole is given by the Avogadro's number as follows;

The number of units of PbO₂ per mole = 6.023 × 10²³ units

The number of units of PbO₂, in 1.36 mole of PbO₂ is therefore;

 = 1.36 × 6.023 × 10²³ units ≈ 8.183 × 10²³ units of PbO₂

The number of units of PbO₂, in 1.36 mole of PbO₂ ≈ 8.183 × 10²³ units.

they both have a y in them

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j