Why does tin oxide weigh more than tin?

hi

Explanation:

The mass of the actual tin will remain constant; however I assume you are comparing the mass of the reactant, tin, with the mass of the products. The increase in mass stems from the oxides of tin present due to its reaction with oxygen in the air:

Sn(s) + O2(g) → SnO2(s)

By working out the atomic mass of the tin and the relative formula mass of tin oxide, you can see why there is a mass increase; 119:151. As you can see here, for every 119g of tin reacted, there will be 151g of tin oxide, hence why you think the mass of the tin increased (by 32g).

Hope this helped!

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o