Binary Ionic Compounds PLEASE HELP AS SOON AS POSSIBLE.
1.) Lead(II)Oxide
2.) Manganese(II) Oxide
3.) Tin(II) Chloride
4.) Iron (III) Oxide
5.) Mercury (II) Bromide
6.) Copper (I) Oxide
7.) Cobalt (III) Chloride
8.) Lead (IV) Oxide
9.) Chromium (III) Chloride
10.) Chrmium (II) Nitride
11.) Ni2S3
12.) V3P4
13.) CoBr2
14.)Cu3N2
15.) SnS2
16.) FeN
17.) Fe2S3
18.) MnCl4
19.) SnO
20.) Co2S3

H=ex5+y intercept

Explanation:

YEAH MA

electron microscopy and scanning tunneling microscopes gives us a greater understanding of atoms by being able to see the atom itself, and lets us see some atomic reactions.

explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2