Barium sulfate is a contrast agent for X-ray scans that are most often associated with the gastrointestinal tract. Calculate the mass of that can dissolve in 340.0 mL of solution. The value for is .

3.07mg of BaSO₄ is the mass that can dissolve in 340.0mL of solution

Explanation:

The Ksp value of BaSO₄ is 1.5x10⁻⁹

The dissolution of BaSO₄ in water follows the equation:

BaSO₄(s) ⇄ Ba²⁺(aq) + SO₄²⁻(aq)

And ksp is defined as:

Ksp = 1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]

As both Ba²⁺ and SO₄²⁻ ions comes from the same salt, the concentration of both ions = The maximum concentration that can be dissolved of BaSO₄ is X:

1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]

1.5x10⁻⁹ = [X] [X]

1.5x10⁻⁹ = X²

X =

3.87x10⁻⁵M = [BaSO₄]

In 340mL = 0.340L, the moles of BaSO₄ are:

0.340L * (3.87x10⁻⁵ moles / L) = 1.317x10⁻⁵ moles of BaSO₄

To convert these moles to the mass in grams we need to use molar mass of BaSO₄ -233.38g/mol-:

1.317x10⁻⁵ moles of BaSO₄ * (233.38g / mol) = 3.07x10⁻³g =

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