Consider the reaction between (R)-4-methyl-1-heptene and BH3 then H2O2, NaOH. Assume that the alkene is enantiomerically pure and optically active. How many new stereoisomers are formed

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the answer is a! (2.9 x 10^-18 j) hope i could someone. : )

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.