A helium laser emits light with a wavelength of 633 nm. What is the frequency, v, of the light?

The frequency, f, of the light emitted at a wavelength of 633 nm is 4.74 × 10¹⁴ Hz

HOW TO CALCULATE WAVELENGTH:

λ = v/f

Where;

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4.74×10¹⁴ Hz.

Explanation:

From the question given above, the following data were obtained:

Wavelength of light = 633 nm.

Frequency of light =?

Next, we shall convert 633 nm to metre (m)

This can be obtained as follow:

1×10⁹ nm = 1 m

Therefore,

633 nm = 633 nm × 1 m / 1×10⁹ nm

633 nm = 6.33×10¯⁷ m

Thus, 633 nm is equivalent to 6.33×10¯⁷ m

Finally, we shall determine the frequency of the light as follow:

Wavelength of light = 6.33×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency of light =?

Velocity = wavelength x frequency

3×10⁸ = 6.33×10¯⁷ x frequency

Divide both side by 6.33×10¯⁷

Frequency = 3×10⁸ / 6.33×10¯⁷

Frequency = 4.74×10¹⁴ Hz.

Therefore, the frequency of the light is 4.74×10¹⁴ Hz.

answer; /// i do believe that the correct answer is (a) boiling

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.