PLEASE I NEED HELP I DONT KNOW THE ANSWER. Fill out the highlighted areas. I will mark brainliest to the first person 4. In each orbital diagram below, Identify the last electron added by notation 1s2 or 1p5 etc.

I think

Explanation:

Li = 2s^1

Be = 2s^2

B = 2p^1

C = 2p^2

I think that is what it is asking if not sorry

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i think   the answer is c hope i'm right