Chemistry, 03.11.2020 03:20 sihamabdalla591
3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O was dissolved in 200. mL of water. 20.0 mL of the solution had some acid added to it and then it reacted completely with 12.6 mL of KMnO4 solution. Calculate the concentration of the KMnO4 solution given the full REDOX equation below. 5Fe2+ + MnO4- + 8H+ --> 5Fe3+ +Mn2+ + 4H2O
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3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O wa...
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