How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction? (HCl molar mass is 36.46 g/mol). BCl3(g) + 3 H2O(l) → 3 HCl(aq) + B(OH)3(aq)

The number of moles of BCl₃ needed is 0.0914 mole

From the question,

We are to determine the number of moles of BCl₃ needed to produce 10.0 g of HCl

From the balanced chemical equation,

BCl₃(g) + 3H₂O(l) → 3HCl(aq) + B(OH)₃(aq)

This means,

1 mole of BCl₃ reacts with 3 moles of H₂O to produce 3 moles of HCl and 1 mole of B(OH)₃

Now, we will determine the number of moles of HCl required to be produced

Mass of HCl = 10.0g

Using the formula

Molar mass of HCl = 36.46 g/mol

∴ Number of moles of HCl required =

Number of moles of HCl required = 0.27427 mole

Since,

1 mole of BCl₃ are needed to produce 3 moles of HCl

Then,

mole of BCl₃ would be needed to produce 0.27427 mole of HCl

∴ 0.0914 mole of BCl₃ would be needed to produce 10.0 g of HCl

Hence, the number of moles of BCl₃ needed is 0.0914 mole

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Moles of BCl₃ needed = 0.089 mol

Explanation:

Given data:

Moles of BCl₃ needed = ?

Mass of HCl produced = 10.0 g

Solution:

Chemical equation:

BCl₃ + 3H₂O  →     3HCl + B(OH)₃

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 36.46 g/mol

Number of moles = 0.27 mol

Now we will compare the moles of HCl with BCl₃.

               HCl             :           BCl₃

                 3               :             1

             0.27             :            1/3×0.27 = 0.089 mol

answer; i believe that the correct answer is (a) potassium(k)

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.