A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done on the gas if it is compressed from 18.38 L to 7.11 L with a pressure of 2.02

2307.17 J

Explanation:

Given data:

Work done = ?

Initial volume = 18.38 L

Final volume = 7.11 L

Pressure = 2.02 atm

Solution:

work done = W = -PΔV

ΔV = V₂- V₁

work done = w = -P(V₂- V₁)

Now we will put the values in formula.

W = - 2.02 atm (7.11 L - 18.38 L)

W = - 2.02 atm (-11.27 L)

W = 22.77 atm.L

atm.L to joule:

22.77 atm.L × 101.325 J / 1L.atm

2307.17 J

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