How many molecules of NH3 are present in 107.1 g?

37.94  × 10²³ molecules of ammonia.

Explanation:

Given data:

Mass of ammonia = 107.1 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of ammonia.

Number of moles = mass/molar molar mass

Number of moles = 107.1 g/  17 g/mol

Number of moles = 6.3 mol

Now we will use the Avogadro number to calculate the number of molecules.

 It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

6.3 mol  × 6.022 × 10²³ molecules / 1mol

37.94  × 10²³ molecules of ammonia.

to make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 ml of water at 80 degrees celsius. when the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.