Aspring requires a force of 25 n to produce an extension of 2 cm in it. what is the work done in further extending it by 3 cm

The work done in further extending spring by 3 cm is 0.5625 Joules.

Explanation:

Force exerted on spring,F = 25 N

Distance up to which spring stretched ,x= 2 cm = 0.02 m

(1 m = 100 cm)

Work done while further stretching the spring by distance x' = 3 cm.

Work done =

The work done in further extending spring by 3 cm is 0.5625 Joules.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

answer seismograph;