How many atoms are in 64 g sulfur (S)? O A. 6.02 x 1023 atoms
OB. 646.02 x 1023) atoms
O C. 32(6.02 x 1023) atoms
D. 2(6.02 x 1023) atoms

D) 2( 6.02 ×10^23)

Explanation:

using n=m

M

where n = moles

m=mass of substance

M=molar mass .

n( sulfur ) =64

32

= 2

using N =nL

where N is number of entities

n = moles

L= 6.02×20^23

N( of atoms of sulfur) =2(6.02×10^23)

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer