In the reaction 2H, + O2 + 2H,0, if you have 3 moles of Hydrogen and 1 mole of oxygen, which is the limiting reactant? Hydrogen
O Oxygen

O₂

Explanation:

A quick way to determine Limiting Reactant => divide moles of each substance given in problem by respective coefficient of balanced equation ... the smaller resulting value is the Limiting Reactant.

                  2H₂        +         O₂        => 2H₂O

Given:   3 moles H₂       1mole O₂

=>            3/2 = 1.5             1/1 = 1

=>   O₂ is Limiting Reactant

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.