Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. 0.500 mole of Ca(NO3)2 in 800.0 mL of solution

[Ca²⁺] = 0.625 M

[NO₃⁻] = 1.25 M

Explanation:

Step 1: Calculate the initial molar concentration of calcium nitrate

[Ca(NO₃)₂] = 0.500 mol / 0.8000 L = 0.625 M

Step 2: Write the reaction for the ionization of calcium nitrate

Calcium nitrate is a strong electrolyte that ionizes according to the following equation.

Ca(NO₃)₂(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq)

Step 3: Calculate the concentrations of the ions

The molar ratio of Ca(NO₃)₂ to Ca²⁺ is 1:1. The concentration of Ca²⁺ is 1/1 × 0.625 M = 0.625 M.

The molar ratio of Ca(NO₃)₂ to NO₃⁻ is 1:2. The concentration of Ca²⁺ is 2/1 × 0.625 M = 1.25 M.

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