Calculate the mass of water that can be vaporized with 1250 calories of energy.

2.31 g

Explanation:

Step 1: Given data

Step 2: Calculate the mass of water that can be vaporized with 1250 calories of energy

We will use the following expression.

Q = ΔH°vap × m

m = Q/ΔH°vap

m = 1250 cal/(540 cal/g)

m = 2.31 g

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the old alchemists made significant contributions to science even though there starting premises were off a bit. their conclusions after failure would steer them into better directions for investigation. science is no more than close observation and the initial mistakes result in rethinking and retrying experiments.