Give the hybridization for the C in HCN. Give the hybridization for the C in HCN. sp3d2 sp3 sp2 sp sp3d

The correct answer is - sp hybridization.

Explanation:

The molecular structure line with a carbon bound to the hydrogen with the single sigma bond and with 2 pi bond and one single sigma bond with carbon Nitrogen triple covalent bond.

To calculate the hybridization of an element like carbon by adding the sigma bond and the lone pair of that atom as here in  HCN molecule, zero lone electrons and two sigmas bond the C atom includes sp-hybridized orbital.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.