A sample of oxygen gas initially at 303 K was heated to 357 K. If the volume of the oxygen gas sample at 357 K is 765.9 mL, what was its volume at 303 K? V= mL

650.04 mL

Explanation:

It is given that,

The volume of the oxygen gas sample at 357 K is 765.9 mL. We need to find the volume of the sample at 303 K.

We know that, the volume is directly proportional to the temperature at constant pressure. It is Charles's law. Its mathematical form is given by :

We have, V₁ = 765.9 mL, T₁ = 357 K, T₂ = 303 K, V₂ =?

Putting all the values,

So, at 303 K, the volume is 650.04 mL.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph