5. An element exists as 2 different isotopes. The first isotope has a mass number of 107 with a percent abundance of 51.853%, and the second isotope has a mass of 109 with an abundance of 48.147%.
What is the average atomic mass of this element? Then, determine the element name.
(Ans = 108.0 amu, Silver)
6. Calculate the average atomic mass of the element Hydrogen (H) using the following data:
Hydrogen-1 99.0%
Hydrogen-2 0.80%
Hydrogen-3 0.20%
(Ans = 1.0 amu)

take a better picture and ill do it

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.