The reaction below takes place in a closed, rigid vessel. The initial pressure of N2(g) is 1.0 atm, and that of O2(g) is 1.5 atm. No N2O4(g) is initially present. The experiment is carried out at a constant temperature. What is the total pressure in the container when the partial pressure of N2O4 reaches 0.75 atm?
N2+O2->N2O4
Please help and explain how you got the answer. I need help on got to get to the answer itself.
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