Chemistry, 23.10.2020 22:50 jade5801

What could happen to homeostasis if the nervous system and the endocrine system stop communicating? Use one specific example in your answer.

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Answer from: kiki197701

The nervous system is in charge of the regulation of all the vital functions, receiving external information, processing it and elaborating an adequate response. When it comes to the internal functions of the organism, the endocrine system receives orders from the nervous system to regulate them and maintain homeostasis.

If there is no communication between Nervous system and the endocrine system, there would be no way to regulate many functions and the organism would lose its ability to maintain internal balance.

⇒For example:

The activity and role of the adrenal glands in response to stress provide an excellent example of interdependency of the nervous and endocrine systems and if there is no communication between the two systems thus there will be no activity of adrenal glands.

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Answer from: ronaa

What could happen if the nervous system and the endocrine system stopped communicating is that body regulation functions would be lost, constituting the loss of organic balance or homeostasis.

Explanation:

There is a close relationship between the nervous and endocrine systems, or what is also known as the neuroendocrine system.

If the communication between Nervous system and the endocrine system did not exist, there would be no way to regulate many functions and the organism would lose its ability to maintain internal balance.

An example of this would be the function of vasopressin or antidiuretic hormone (ADH). This hormone is produced by the hypothalamus and released by the neurohypophysis, being its main function the regulation of the hydroelectrolytic balance. If the communication between both systems did not exist, the function of ADH would not be possible, and the hydroelectrolytic balance would be lost.

What could happen to homeostasis if the nervous system and the endocrine system stop communicating?

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

Answer from: Quest

the answer is 303.15 or 303

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