Cobalt-60 is an artificial radioisotope that is produced in a nuclear reactor for use as a gamma-ray source in the treatment of certain types of cancer. If the wavelength of the gamma radiation from Co-60 is 2.00 x 10-12 m, calculate the energy of a photon of this radiation.

E = 9.93 x 10^-14 J

Explanation:

Wavelength, λ = 2.00 x 10-12 m

Energy, E = ?

Relationship between both quantities is given as;

E = hc/λ

where;

c = speed of light = 2.998  ×  10 8  m⋅s −1

h = Plank's constant = 6.626*10-34 Js

Solving for E;

E = 6.626*10^-34 * 2.998  ×  10^ 8 / 2.00 x 10^-12

E = 9.93 x 10^-14 J

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)