A 57.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water should be added

The amount of water to add is 171 mL

Explanation:

A solution is a homogeneous mixture of two or more substances.

A dilution is a solution with a lower concentration than the one you start from, called the stock solution.

In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent. In other words, in a dilution the amount of solute does not vary, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, since the volume (and weight) of the solution increases.

The formula used in dilution is:

Ci*Vi = Cf*Vf

where

In this case:

So:

0.400 M* 0.057 L= 0.100 M*Vf

Solving for Vf:

Vf=0.228 L

Assuming that the volumes are additive, the final volume is equal to the initial volume plus the amount of water added:

Vf= Vi + Vwater added

Then:

0.228 L= 0.057 L + Vwater added

Solving:

Vwater added= 0.228 L - 0.057 L

Vwater added= 0.171 L= 171 mL

The amount of water to add is 171 mL

a c d and f

just finished the assignment

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