Using a triple beam balance and a graduated cylinder, a student collected data on a sample of an element:Mass of sample = 18.9 gVolume of water = 30.0 mLVolume of water and sample = 35.0 mL using SigFig Rules *

The question is incomplete; the complete question is;

Using a triple beam balance and a graduated cylinder, a student collected data on a sample of an element:

Mass of sample = 18.9 g

Volume of water = 30.0 mL

Volume of water and sample = 35.0 mL

Calculate the density of the sample using sig figs.

3.8 g/mL

Explanation:

Mass of sample = 18.9 g

Volume of water = 30.0 mL

Volume of water and sample = 35.0 mL

Volume of the sample = 35.0 mL – 30.0 mL = 5.0 mL

D = m/v

D = 18.9 g / 5.0 mL =3.8 g/mL

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2