The combustion of ethane (C2H6) produces carbon dioxide and steam. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) How many moles of CO2 are produced when 5.90 mol of ethane is burned in an excess of oxygen?

11.8 moles of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

From the balanced equation above,

2 moles of C2H6 reacted with 7 moles of O2 to produce 4 moles of CO2 and 6 moles of H2O.

Thus, we can obtain the number of moles of CO2 produced when 5.9 moles of C2H6 is burned in excess O2 as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 4 moles of CO2.

Therefore, 5.9 moles of C2H6 will react to produce = (5.9 × 4)/2 = 11.8 moles of CO2.

Thus, 11.8 moles of CO2 were obtained from the reaction.