What is the heat of a reaction, in joules, with a total reaction mixture volume of 62.3 mL of the reaction causes a temperature change of 5.0 oC in a calorimeter

1,303.316 J = 1.303316 KJ.

Explanation:

The first thing to do is to calculate or Determine the mass. Thus, from the question/problem above some basic parameters or data or information were provided which is going to aid in solving this particular Question;

=> total reaction mixture volume =62.3 mL and the reaction temperature change = of 5.0 oC

The mass = density × total reaction mixture volume = 1 × 62.3 = 62.3 grams.

Therefore, the heat of a reaction = mass × specific heat capacity (C) × temperature change (∆T).

Thus, the heat of reaction = 62.3 grams × 4.184 J/g-°C × 5.0°C = 1,303.316 J = 1.303316 KJ.

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .