The Kp for the reaction A (g) = 2 B (g) is 0.0380. What is Kp for the reaction 4 B (g) = 2 A (g)?

692.52

Explanation:

First Reaction;

A (g) = 2 B (g)

Kp is given as; (PB)² / (PA)

But Kp = 0.0380

So we have;

(PB)² / (PA)  = 0.0380

Second Reaction;

4 B (g) = 2 A (g)

Kp is given as; (PA)² / (PB)⁴

The relationship between Kp expressions for both reactions is given as;

Second Reaction Kp = 1 / (First Reaction Kp)²

Second Reaction Kp = 1 / (0.0380)²  = 1/0.001444

Second Reaction Kp = 692.52

i would say b

explanation:

but i think i would need more information than that

so what is the problem with your lab report and whats the subject of the lab report? i will you