Calculate the freezing point of a solution containing 10 grams of KCl and 1100.0 grams of water. The molal freezing point depression constant (Kf) for water is 1.86

- 0.454 °C

Explanation:

From the given information:

The mass of KCl = 10 grams

The molar mass of KCl = 74.55 g/mol

The molality can be calculated as:

Molality m = 0.1219 M

For freezing point depression;

The van't Hoff's Factor (i) for KCl  = 2

The molar depression of freezing point constant = 1.86° C/m

∴

However, the freezing point of water is known to be = 0°C

Therefore, the freezing point of the solution

= 0 °C - 0.454 °C

= - 0.454 °C

i'm assuming that the correct answer is indeed the first one/ "a"..