In the KHP titration, imagine a student fills his buret with NaOH solution imediately after rinsing it with water and after reading the initial volume, begins the titration. He skips the step in which the buret is rinsed with a small amount of the NaOH. How is this oversight likely to reflect in his calculation of the molarity of the NaOH? Explain your reasoning in detail.

Explanation:

Since the student fills up the buret with NaOH without rinsing it with small amount of NaOH , the water that is remaining stuck with the walls of the buret will dilute the solution of NaOH and it will result in lowering the morality of the solution . The molar concentration of the NaOH will no longer remain the same . It will lead to wrong calculation and hence wrong result.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2