The ba(oh)2 dissociates as ba+2 + 2 oh-. h2so4 dissociates as 2 h+ + so4-2. when the conductivity is at a minimum, what must be true about the amount of ba(oh)2 compared to h2so4? also, why does it not conduct at this low point?

Consider the following reaction at equilibrium: c(s)+h2o(g)⇌co(g)+h2(g) predict whether the reaction will shift left, shift right, or remain unchanged upon each of the following disturbances. a) c is added to the reaction mixture. b) h2ois condensed and removed from the reaction mixture c) co is added to the reaction mixture d) h2 is removed from the reaction mixture.