calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00 g of CaCO3 (s). There is an excess of Na2CO3. Volume of calcium chloride in mL

1.00 × 10² mL

Explanation:

Step 1: Write the balanced equation

CaCl₂ + Na₂CO₃ ⇒ CaCO₃ + 2 NaCl

Step 2: Calculate the moles corresponding to 1.00 g of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

1.00 g × (1 mol/100.09 g) = 0.0100 mol

Step 3: Calculate the moles of CaCl₂ required to produce 0.0100 moles of CaCO₃

The molar ratio of CaCl₂ to CaCO₃ is 1:1. The moles of CaCl₂ are 1/1 × 0.0100 mol = 0.0100 mol.

Step 4: Calculate the volume of 0.100 M CaCl₂ solution that contains 0.0100 mol

0.0100 mol × (1 L/0.100 mol) × (1000 mL/1 L) = 1.00 × 10² mL

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