A 10.04-g block of solid tin at 14.77 °C is immersed in a 24.11-g pool of liquid ethylene glycol with a temperature of 63.52 °C. When thermal equilibrium is reached, what is the temperature of the tin and ethylene glycol? Specific heat capacities: tin = 0.213 J/g °C; ethylene glycol = 2.36 J/g °C

61.75 °C

Explanation:

According to the law of conservation of energy,

Qtin = - (Qliquid)

(m×c×∆T)tin = -(m×c×∆T) ethylene glycol

Where; m = mass

c = specific heat capacity

∆T = change in temperature

According to the information given in this question;

For tin: m= 10.04g, c= 0.213 J/g °C, initial temperature= 14.77 °C, final temperature=?

For ethylene glycol: m= 24.11g, c= 2.36 J/g °C, initial temperature= 63.52 °C, final temperature=?

Hence; (m×c×∆T)tin = -(m×c×∆T) ethylene glycol

10.04 × 0.213 × (T - 14.77) = - {24.11 × 2.36 × (T - 63.52)}

2.139 (T - 14.77) = - {56.899 (T - 63.52)}

2.139T - 31.59 = -56.899T + 3614.225

2.139T + 56.899T = 31.59 + 3614.225

59.038T = 3645.815

T = 3645.815/59.038

T = 61.75 °C

The final temperature of tin and ethylene glycol is 61.75 °C

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

the answer is yes

it has kinetic energy

reason

an object has kinetic energy when you stop the force carrying it, the object will stay in motion.

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