Standard enthalpy of combustion of graphite at 25 oC is –393.51 kJ mol -1 and that of diamond
is –395.41 kJ mol-1
. The enthalpy change for graphite is:
A) – 1.91 C) –2.1
B) +2.1 D) +1.91

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

the ratio of the conjugate base to the acid required to attain the desired ph.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.