Danielle is asked to determine the density and the identity of a metal. She determines the mass of the metal to be 102.06g and then determines the volume of the sample using water displacement. Find the density. Round the answer to the nearest whole number?

11 g/mL

Explanation:

From the question given above, the following data were obtained:

Mass of metal = 102.06 g

Volume of water = 38 mL

Volume of water + metal = 47 mL

Density of metal =.?

Next, we shall determine the volume of the metal. This can be obtained as shown below:

Volume of water = 38 mL

Volume of water + metal = 47 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water)

Volume of metal = 47 – 38

Volume of metal = 9 mL

Finally, we shall determine the density of the metal as follow:

Mass of metal = 102.06 g

Volume of metal = 9 mL

Density of metal =.?

Density = mass /volume

Density of metal = 102.06 / 9

Density of metal = 11.34 ≈ 11 g/mL

Therefore, the density of the metal is 11 g/mL

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.