Using the balanced equation below, how many grams of cesium xenon
heptafluoride would be produced
from the complete reaction of 37.8 g
cesium fluoride?

CsF + XeF6 => CsXeF7

Mass of CsXeF₇  = 99.3 g

Explanation:

Given data:

Mass of CsF = 37.8 g

Mass of CsXeF₇ produced = ?

Solution:

Balance chemical equation:

CsF + XeF₆   →    CsXeF₇

Number of moles of CsF:

Number of moles = mass/molar mass

Number of moles = 37.8 g/ 152 g/mol

Number of moles = 0.25 mol

Now we will compare the moles of CsF with CsXeF₇  from balance chemical equation:      

                   CsF             :         CsXeF₇

                    1                 :             1

                 0.25             :           0.25

Mass of CsXeF₇ :

Mass = number of moles × molar mass

Number of moles = 0.25 mol × 397.2 g/mol

Mass = 99.3 g