PLEASE HELP!! There are 5.5 L of a gas present at -38.0 C. What is the temperature if the volume of the gas has changed to 1.30 L?

Explanation:

In order to find out the final temperature we use the formula for Charles's law which is

where

V1 is the initial volume

T1 is the initial temperature in Kelvin

V2 is the final volume

T2 is the final temperature in Kelvin

Since we are finding the final temperature

rom the question

V1 = 5.5 L

T1 = -38°C = -38 + 273 = 235 K

V2 = 1.30 L

We have

We have the final answer as

Hope this helps you

a

explanation:

imma come back to you hold on