A sample of gas occupies a volume of 7.50 L at 28.0C. At what temperature is the volume of the gas 4.00 L if the pressure is kept constant.

Explanation:

To solve this, you must use Charles' Law:

V1/T1 = V2/T2

The values given are:

V1 = 7.50 L

V2 = 4.00 L

Temperature must be in Kelvin

Conversion: 28+273 = 301 K

Substitute values in Charles' Law:

7.50L /301 K = 4.00/T2

Cross-Multiply:

(7.50)(T2) = 1204

Solve for T2:

T2 = 160.53 K or -112.47˚C

This makes sense, as volume and temperature are directly proportional. As V increases, so will T and vice versa.

can you attach a picture of the lettuce? : )

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter