4 (NH4)3PO4+ 3 Pb(NO3)4 → 1Pb3(PO4)4+ 12 NH4NO3 If I start with 53L Pb(NO3), how many particles of Pb3(PO4)4 will be produced?
Answer must must be typed in useing "e". For example 6.02 x 1023 would be 6.02e23.

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