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2A + 5B --> 3C + D

2.0 mol A and 4.0 mol B react to form 1.8 mol C. What is the PERCENT YIELD of this reaction?

Percent yield of reaction is 75%.

Explanation:

Given data:

Moles of A = 2.0 mol

Moles of B = 4.0 mol

Moles of C formed = 1.8 mol

Percent yield of reaction = ?

Solution:

Chemical equation:

2A + 5B     →      3C +  D

We will compare the moles of A and B with C from balance chemical equation.

                A         :          C

                2         :           3

               B          :         C

                 5         :         3

                 4         :        3/5×4 = 2.4 mol

Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.

Percent yield:

Percent yield =  actual yield /theoretical yield × 100

Percent yield = 1.8 mol / 2.4  × 100

Percent yield =75%

if you're asking what comes out, it's steam.