50.00 mL of a solution containing 0.15 M CH2 (CO2 H)2 and 0.020 M MnSO4 1. Calculate the mass in g of malonic acid required.

Watch your sig figs! (enter just the number)

Explanation:

Hello.

In this case, for the given volume and molarity of malonic acid (solute), we can compute the mass by first computing the moles considering the definition of molarity:

Then, since the molar mass of the malonic acid is 104.1 g/mol, we can compute the required mass in g of malonic acid for the preparation of that solution as shown below:

Notice that the shortest number is the molarity (0.15 M) with two significant figures, that is why the answer is displayed with two significant figures too.

Regards.

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.