Which of the following is the correct Lewis Dot Structure for MgBr2?
PHOTO ABOVE

Option A

Explanation:

To know the correct answer to the question, let us write an equation illustrating the formation of MgBr₂.

This is illustrated below:

1. Magnesium (Mg) is divalent element hence it will lose 2 electrons to form magnesium ion (Mg²⁺) as shown below

Mg —> Mg²⁺ + 2e¯

2. Bromine (Br) is a univalent element. Two bromine atom will receive the two electrons (i.e each atom receives 1 electron) to form the bromide ion (Br¯) as shown below:

2Br + 2e¯ —> 2Br¯

Combine both equation

Mg + 2Br + 2e¯—> Mg²⁺ + 2e¯ + 2Br¯

Cancel out 2e¯

Mg + 2Br —> Mg²⁺ + 2Br¯

Thus we have

Br—Mg—Br

From the illustration made above, we can see that two bromine atom is receiving 1 electron each from the magnesium atom

i believe it is c.) 1575 j.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3