ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST An atom of rubidium has 37 protons and 48 neutrons. The atom loses one electron.
What will be the charge on the ion that forms?

36
+1
−36
−1

-136

Step-by-step explanation:

"Loses" means subtraction, decrease, or negative. So, a loss of 1, can also be represented by -1.If protons and electrons can be represented by the same number (37), then a loss of 1 is just, 37 - 1. 37 - 1 = 36.

I hope this helps!

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .