What is the concentration of lithium ions in 0.390 M Li3PO4?

1.17 M

Explanation:

Step 1: Given data

Molar concentration of Li₃PO₄: 0.390 M

Step 2: Write the reaction for the dissociation of Li₃PO₄

Lithium phosphate is a strong electrolyte that dissociates according to the following equation:

Li₃PO₄(aq) ⇒ 3 Li⁺(aq) + PO₄³⁻(aq)

Step 3: Calculate the molar concentration of lithium ions

The molar ratio of Li₃PO₄ to Li⁺ is 1:3. The molar concentration of Li⁺ is 3/1 × 0.390 M = 1.17 M.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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