If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? The other products are hydroxide ion and water.

Explanation:

Hello,

In this case, given the balanced reaction:

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

Best regards.

i would say b

explanation:

but i think i would need more information than that

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i think? ?