You find that the mass of a cube of aluminum is 2.85 kilograms. You up the density of aluminum and find it to be 2.70 g/cm^3? What is the volume of the cube? (HINT: you have to rearrange the formula p=m/v).* A.0.00095 cm^3
B. 1.055 cm^3
C. 7.695 cm^3
D. 1,055.5 cm^3

Percent error = 5.6%

Explanation:

Given data:

Measured value of density by students = 2.85 g/cm³

Accepted density of aluminium = 2.70 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [ Measured value - accepted value / accepted value ]× 100

Now we will put the values in formula:

Percent error = [ 2.85 g/cm³  - 2.70 g/cm³ / 2.70 g/cm³ ]× 100

Percent error = [0.15/2.70 g/cm³ ] × 100

Percent error = 0.056× 100

Percent error = 5.6%

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.