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  17 (a) 360,000 ms         18 (a) 0.245 s

                     (b) 4.800 kg                   (b) 500 cm

                     (c) 560.0 dm                  (c) 68.00 m

                     (d) 72,000 mg                (d) 0.025 Mg

Explanation:

Use the following table.  Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.

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17(a) 360 s to ms                                                        o       →         →        →o

Move the decimal 3 places to the right   -->   360_ _ _.

Fill in the blanks with zeroes   --> 360,000

  (b) 4800 g to kg                            o←    ←     ←         o

Move the decimal 3 places to the left   --> 4.8 0 0

 (c) 5600 dm to m                                                       o←     o

Move the decimal 1 place to the left   --> 560. 0

 (d)  72 g to mg                                                         o         →        →        →o

Move the decimal 3 places to the right   --> 72 _ _ _.

Fill in the blanks with zeroes   -->     72,000

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18 (a) 245 ms to s                                                       o←       ←       ←        o

Move the decimal 3 places to the left -->   . 2 4 5

     (b) 5 m to cm                                                        o        →        →o

Move the decimal 2 places to the right   -->   5 _ _.

Fill in the blanks with zeroes   -->    500

      (c) 6800 cm to m                                                 o←      ←        o

Move the decimal 2 places to the left   -->   68. 0 0

    (d)  25 kg to Mg    o←    ←    ←    o

Move the decimal 3 places to the left -->   . _ 25

Fill in the blanks with zeroes  -->   .025

im pretty sure its b

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.