Steven had a sample of ethanol and wanted to see if it would boil at the temperature found in his textbook. His experiment yielded a temperature of 143.6oF but the literature value was 173.1oF. What is the percent error in this experiment?

17.04%

Explanation:

Actual Value = 173.1

Measured Value = 143.6

Percent error is obtained using the equation;

Percent error = (Measured - Actual) / Actual ]* 100

Percent error = [ (143.6 - 173.1) / 173.1 ] * 100

The absolute value of (Measured - Actual) is taken,

Percent Error = [29.5 / 173.1 ] * 100

Percent Error = 0.1704 * 100 = 17.04%

the answer is a and have a great day