6. Which best represents a particle containing 28 protons, 26 electrons, and 34 neutrons?
A Fe2-
B
54
2+
28N;
C%2Fe2-
DSNi2+

Ni^2+

Explanation:

The following data were obtained from the question:

Proton = 28

Electron = 26

Neutron = 34

Next, we shall determine the atomic number of the element.

Atomic number of an element is simply defined as the number of protons in the atom of an element.

Thus,

Atomic number = proton number

Proton = 28

Atomic number = proton number = 28

Atomic number = 28

Therefore, the element is Nickel since no two elements have the same atomic number.

Finally, we shall determine the charge on the Nickel atom as follow:

Proton = 28

Electron = 26

Charge on atom =

Charge on atom = Proton – Electron

Charge on atom = 28 – 26

Charge on atom = +2

Therefore, we can represent the Particle as Ni^2+

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :