The cloth shroud from around a mummy is found to have a 14C activity of 8.4 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon. From the half-life for 14C decay, 5715 yr, calculate the age of the shroud

48889 years

Explanation:

Activity of the living sample Ao= 15.2 disintegration per minute

Activity of the cloth A= 8.4 disintegration per minute

Half life of 14C= 5715 years

Time taken for the decay t= the unknown

From;

0.693/5715 = 2.303/t log (15.2/8.4)

1.213 × 10^-4 = 2.303/t log (1.8095)

1.213 × 10^-4 = 0.593/t

t= 0.593/1.213 × 10^-4

t= 4888.7 years

t= 48889 years

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml