Chemistry, 01.09.2020 16:01 faithkristi

i’m stuck on part b of this question :( this is from the ap chem textbook on pg. 35 just so u know. please help!

i’m stuck on part b of this question :( this is from the ap chem textbook on pg. 35 just so u know.

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Answer from: kyleee4473

b) Aluminum sphere: 11.4J

Silver sphere: 44.3 J

Explanation:

a) Mass of aluminum sphere

= 2.70(196)

= 529.20g

= 0.5292kg

Mass of silver sphere

= 10.49(196)

= 2056.04g

= 2.05604 kg

b) Work done (Joules)

= force (Newton) ×distance moved in the direction of the force (in meters)

$\boxed{W = F \times d}$

To raise the sphere, the work done is against gravity.

For the formula for weight (or force of gravity), the mass needed is in kg, which we have already converted to in part (a).

Since they asked for the work done on each sphere, let's calculate the work done for the aluminium sphere first.

Aluminium sphere:

F= mg

F= 0.5292(9.8)

F= 5.18616N

W= Fd

Work done

= 5.18616(2.2)

= 11.4J (3 s.f.)

Silver sphere:

F= mg

F= 2.05604(9.8)

F= 20.149192N

W= Fd

Work done

= 20.149192(2.2)

= 44.3J (3 s.f.)

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

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i’m stuck on part b of this question :( this is from the ap chem textbook on pg. 35 just so u know....

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